1400413433121 has 6 divisors (see below), whose sum is σ = 2022819403410. Its totient is φ = 933608955408.

The previous prime is 1400413433113. The next prime is 1400413433203. The reversal of 1400413433121 is 1213343140041.

1400413433121 is a `hidden beast` number, since 1 + 4 + 0 + 0 + 4 + 1 + 343 + 312 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 1140656040225 + 259757392896 = 1068015^2 + 509664^2 .

It is not a de Polignac number, because 1400413433121 - 2³ = 1400413433113 is a prime.

It is a super-2 number, since 2×1400413433121² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1400413033121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 77800746276 + ... + 77800746293.

It is an arithmetic number, because the mean of its divisors is an integer number (337136567235).

Almost surely, 2^{1400413433121} is an apocalyptic number.

It is an amenable number.

1400413433121 is a deficient number, since it is larger than the sum of its proper divisors (622405970289).

1400413433121 is a wasteful number, since it uses less digits than its factorization.

1400413433121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 155601492575 (or 155601492572 counting only the distinct ones).

The product of its (nonzero) digits is 3456, while the sum is 27.

Adding to 1400413433121 its reverse (1213343140041), we get a palindrome (2613756573162).

The spelling of 1400413433121 in words is "one trillion, four hundred billion, four hundred thirteen million, four hundred thirty-three thousand, one hundred twenty-one".