140042344424121 has 6 divisors (see below), whose sum is σ = 202283386390410. Its totient is φ = 93361562949408.

The previous prime is 140042344424117. The next prime is 140042344424173. The reversal of 140042344424121 is 121424443240041.

140042344424121 is a `hidden beast` number, since 1 + 4 + 0 + 0 + 4 + 234 + 4 + 4 + 2 + 412 + 1 = 666.

It can be written as a sum of positive squares in only one way, i.e., 132323610240000 + 7718734184121 = 11503200^2 + 2778261^2 .

It is not a de Polignac number, because 140042344424121 - 2² = 140042344424117 is a prime.

It is a super-2 number, since 2×140042344424121² (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (140042544424121) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 7780130245776 + ... + 7780130245793.

It is an arithmetic number, because the mean of its divisors is an integer number (33713897731735).

Almost surely, 2^{140042344424121} is an apocalyptic number.

It is an amenable number.

140042344424121 is a deficient number, since it is larger than the sum of its proper divisors (62241041966289).

140042344424121 is a wasteful number, since it uses less digits than its factorization.

140042344424121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15560260491575 (or 15560260491572 counting only the distinct ones).

The product of its (nonzero) digits is 98304, while the sum is 36.

Adding to 140042344424121 its reverse (121424443240041), we get a palindrome (261466787664162).

The spelling of 140042344424121 in words is "one hundred forty trillion, forty-two billion, three hundred forty-four million, four hundred twenty-four thousand, one hundred twenty-one".