140044213340041 has 4 divisors (see below), whose sum is σ = 144873324144900. Its totient is φ = 135215102535184.

The previous prime is 140044213340039. The next prime is 140044213340167. The reversal of 140044213340041 is 140043312440041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 56094108160000 + 83950105180041 = 7489600^2 + 9162429^2 .

It is a cyclic number.

It is not a de Polignac number, because 140044213340041 - 2¹ = 140044213340039 is a prime.

It is a super-2 number, since 2×140044213340041² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140044213339985 and 140044213340012.

It is not an unprimeable number, because it can be changed into a prime (140044213340021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2414555402386 + ... + 2414555402443.

It is an arithmetic number, because the mean of its divisors is an integer number (36218331036225).

Almost surely, 2^{140044213340041} is an apocalyptic number.

It is an amenable number.

140044213340041 is a deficient number, since it is larger than the sum of its proper divisors (4829110804859).

140044213340041 is an equidigital number, since it uses as much as digits as its factorization.

140044213340041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4829110804858.

The product of its (nonzero) digits is 18432, while the sum is 31.

Adding to 140044213340041 its reverse (140043312440041), we get a palindrome (280087525780082).

The spelling of 140044213340041 in words is "one hundred forty trillion, forty-four billion, two hundred thirteen million, three hundred forty thousand, forty-one".