Search a number
-
+
14004433211 = 47911292301
BaseRepresentation
bin11010000101011101…
…01011000100111011
31100010222210220210112
431002232223010323
5212140113330321
610233351334535
71004020501226
oct150256530473
940128726715
1014004433211
115a37156a4a
12286a08144b
131422501992
1496bd0c5bd
1556e70ba5b
hex342bab13b

14004433211 has 4 divisors (see below), whose sum is σ = 14004773424. Its totient is φ = 14004093000.

The previous prime is 14004433207. The next prime is 14004433229. The reversal of 14004433211 is 11233440041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11233440041 = 31913520351.

It is a cyclic number.

It is not a de Polignac number, because 14004433211 - 22 = 14004433207 is a prime.

It is a super-2 number, since 2×140044332112 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14004433231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98240 + ... + 194061.

It is an arithmetic number, because the mean of its divisors is an integer number (3501193356).

Almost surely, 214004433211 is an apocalyptic number.

14004433211 is a deficient number, since it is larger than the sum of its proper divisors (340213).

14004433211 is an equidigital number, since it uses as much as digits as its factorization.

14004433211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 340212.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14004433211 its reverse (11233440041), we get a palindrome (25237873252).

The spelling of 14004433211 in words is "fourteen billion, four million, four hundred thirty-three thousand, two hundred eleven".

Divisors: 1 47911 292301 14004433211