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14005113353 = 711181884589
BaseRepresentation
bin11010000101100010…
…10001001000001001
31100011001002110202222
431002301101020021
5212140302111403
610233414103425
71004026333160
oct150261211011
940131073688
1014005113353
115a37580a50
12286a34ab75
1314226ac42a
1496c0483d7
1556e7e3338
hex342c51209

14005113353 has 8 divisors (see below), whose sum is σ = 17460920640. Its totient is φ = 10913075280.

The previous prime is 14005113299. The next prime is 14005113361. The reversal of 14005113353 is 35331150041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14005113353 - 212 = 14005109257 is a prime.

It is a super-2 number, since 2×140051133532 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14005113253) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 90942218 + ... + 90942371.

It is an arithmetic number, because the mean of its divisors is an integer number (2182615080).

Almost surely, 214005113353 is an apocalyptic number.

It is an amenable number.

14005113353 is a deficient number, since it is larger than the sum of its proper divisors (3455807287).

14005113353 is a wasteful number, since it uses less digits than its factorization.

14005113353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 181884607.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 14005113353 its reverse (35331150041), we get a palindrome (49336263394).

The spelling of 14005113353 in words is "fourteen billion, five million, one hundred thirteen thousand, three hundred fifty-three".

Divisors: 1 7 11 77 181884589 1273192123 2000730479 14005113353