Base | Representation |
---|---|
bin | 10100011000110010000… |
… | …111010010011111011001 |
3 | 11221221020002212122112111 |
4 | 110120302013102133121 |
5 | 140423222012010131 |
6 | 2551335514312321 |
7 | 203135042306530 |
oct | 24306207223731 |
9 | 4857202778474 |
10 | 1401000110041 |
11 | 4a0185046814 |
12 | 1a76341286a1 |
13 | a2162b8216c |
14 | 4bb47385317 |
15 | 2669ad63ab1 |
hex | 146321d27d9 |
1401000110041 has 4 divisors (see below), whose sum is σ = 1601142982912. Its totient is φ = 1200857237172.
The previous prime is 1401000110033. The next prime is 1401000110053. The reversal of 1401000110041 is 1400110001041.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1401000110041 - 23 = 1401000110033 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1401000110941) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100071436425 + ... + 100071436438.
It is an arithmetic number, because the mean of its divisors is an integer number (400285745728).
Almost surely, 21401000110041 is an apocalyptic number.
It is an amenable number.
1401000110041 is a deficient number, since it is larger than the sum of its proper divisors (200142872871).
1401000110041 is an equidigital number, since it uses as much as digits as its factorization.
1401000110041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 200142872870.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 1401000110041 its reverse (1400110001041), we get a palindrome (2801110111082).
The spelling of 1401000110041 in words is "one trillion, four hundred one billion, one hundred ten thousand, forty-one".
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