140101311323 has 4 divisors (see below), whose sum is σ = 142475909880. Its totient is φ = 137726712768.

The previous prime is 140101311281. The next prime is 140101311403. The reversal of 140101311323 is 323113101041.

140101311323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140101311323 - 2¹⁶ = 140101245787 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140101311295 and 140101311304.

It is not an unprimeable number, because it can be changed into a prime (140101314323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1187299190 + ... + 1187299307.

It is an arithmetic number, because the mean of its divisors is an integer number (35618977470).

Almost surely, 2^140101311323 is an apocalyptic number.

140101311323 is a deficient number, since it is larger than the sum of its proper divisors (2374598557).

140101311323 is an equidigital number, since it uses as much as digits as its factorization.

140101311323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2374598556.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 140101311323 its reverse (323113101041), we get a palindrome (463214412364).

The spelling of 140101311323 in words is "one hundred forty billion, one hundred one million, three hundred eleven thousand, three hundred twenty-three".