Base | Representation |
---|---|
bin | 11111110110110010000011… |
… | …000101000101010000001011 |
3 | 200101001210222220110010121211 |
4 | 133312302003011011100023 |
5 | 121330431024234434201 |
6 | 1213550523125113551 |
7 | 41340116346435550 |
oct | 3766620305052013 |
9 | 611053886403554 |
10 | 140104032343051 |
11 | 40706871831367 |
12 | 13869124b588b7 |
13 | 60239a475713a |
14 | 26850ddac0a27 |
15 | 112e662739651 |
hex | 7f6c8314540b |
140104032343051 has 8 divisors (see below), whose sum is σ = 160118971568640. Its totient is φ = 120089112483048.
The previous prime is 140104032343003. The next prime is 140104032343073. The reversal of 140104032343051 is 150343230401041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 140104032343051 - 211 = 140104032341003 is a prime.
It is not an unprimeable number, because it can be changed into a prime (140104032343081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17590560 + ... + 24282418.
It is an arithmetic number, because the mean of its divisors is an integer number (20014871446080).
Almost surely, 2140104032343051 is an apocalyptic number.
140104032343051 is a deficient number, since it is larger than the sum of its proper divisors (20014939225589).
140104032343051 is an equidigital number, since it uses as much as digits as its factorization.
140104032343051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9682793.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 140104032343051 its reverse (150343230401041), we get a palindrome (290447262744092).
The spelling of 140104032343051 in words is "one hundred forty trillion, one hundred four billion, thirty-two million, three hundred forty-three thousand, fifty-one".
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