Base | Representation |
---|---|
bin | 10100011000110100100… |
… | …011100010110101001011 |
3 | 11221221022221221201000011 |
4 | 110120310203202311023 |
5 | 140423313003241220 |
6 | 2551343540252351 |
7 | 203136050420515 |
oct | 24306443426513 |
9 | 4857287851004 |
10 | 1401041071435 |
11 | 4a01a6183705 |
12 | 1a76459a10b7 |
13 | a216b4c4485 |
14 | 4bb4c9a8bb5 |
15 | 2669e75565a |
hex | 146348e2d4b |
1401041071435 has 8 divisors (see below), whose sum is σ = 1681255771920. Its totient is φ = 1120828533024.
The previous prime is 1401041071403. The next prime is 1401041071499. The reversal of 1401041071435 is 5341701401041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1401041071435 - 25 = 1401041071403 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1401041071397 and 1401041071406.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1831101 + ... + 2480929.
It is an arithmetic number, because the mean of its divisors is an integer number (210156971490).
Almost surely, 21401041071435 is an apocalyptic number.
1401041071435 is a deficient number, since it is larger than the sum of its proper divisors (280214700485).
1401041071435 is an equidigital number, since it uses as much as digits as its factorization.
1401041071435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1081037.
The product of its (nonzero) digits is 6720, while the sum is 31.
Adding to 1401041071435 its reverse (5341701401041), we get a palindrome (6742742472476).
The spelling of 1401041071435 in words is "one trillion, four hundred one billion, forty-one million, seventy-one thousand, four hundred thirty-five".
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