Base | Representation |
---|---|
bin | 1100101111100011000110… |
… | …0010001101011101001011 |
3 | 1211121102212200101222111122 |
4 | 3023320301202031131023 |
5 | 3314024024134334042 |
6 | 45444323211145455 |
7 | 2644155666066563 |
oct | 313706142153513 |
9 | 54542780358448 |
10 | 14011014371147 |
11 | 4512046389762 |
12 | 16a351844528b |
13 | 7a8304b40921 |
14 | 3661cb1ddda3 |
15 | 1946d2d7a7d2 |
hex | cbe3188d74b |
14011014371147 has 8 divisors (see below), whose sum is σ = 14217265904640. Its totient is φ = 13805485260840.
The previous prime is 14011014371143. The next prime is 14011014371161. The reversal of 14011014371147 is 74117341011041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14011014371147 - 22 = 14011014371143 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14011014371143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 180566723 + ... + 180644300.
It is an arithmetic number, because the mean of its divisors is an integer number (1777158238080).
Almost surely, 214011014371147 is an apocalyptic number.
14011014371147 is a deficient number, since it is larger than the sum of its proper divisors (206251533493).
14011014371147 is an equidigital number, since it uses as much as digits as its factorization.
14011014371147 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 361211593.
The product of its (nonzero) digits is 9408, while the sum is 35.
Adding to 14011014371147 its reverse (74117341011041), we get a palindrome (88128355382188).
The spelling of 14011014371147 in words is "fourteen trillion, eleven billion, fourteen million, three hundred seventy-one thousand, one hundred forty-seven".
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