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140110535035 = 528022107007
BaseRepresentation
bin1000001001111100111…
…1010001100101111011
3111101122112200122022101
42002133033101211323
54243421244110120
6144211011004231
713060032616612
oct2023717214573
9441575618271
10140110535035
1154469820809
12231a2899677
131029b753a43
146ad21a2879
1539a07a790a
hex209f3d197b

140110535035 has 4 divisors (see below), whose sum is σ = 168132642048. Its totient is φ = 112088428024.

The previous prime is 140110535017. The next prime is 140110535113. The reversal of 140110535035 is 530535011041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140110535035 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140110534994 and 140110535012.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14011053499 + ... + 14011053508.

It is an arithmetic number, because the mean of its divisors is an integer number (42033160512).

Almost surely, 2140110535035 is an apocalyptic number.

140110535035 is a deficient number, since it is larger than the sum of its proper divisors (28022107013).

140110535035 is an equidigital number, since it uses as much as digits as its factorization.

140110535035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28022107012.

The product of its (nonzero) digits is 4500, while the sum is 28.

Adding to 140110535035 its reverse (530535011041), we get a palindrome (670645546076).

The spelling of 140110535035 in words is "one hundred forty billion, one hundred ten million, five hundred thirty-five thousand, thirty-five".

Divisors: 1 5 28022107007 140110535035