1401111433 has 8 divisors (see below), whose sum is σ = 1522430720. Its totient is φ = 1284549840.

The previous prime is 1401111403. The next prime is 1401111443. The reversal of 1401111433 is 3341111041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1401111433 is a prime.

It is a super-2 number, since 2×1401111433² = 3926226495366626978, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (19).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1401111433.

It is not an unprimeable number, because it can be changed into a prime (1401111403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1188810 + ... + 1189987.

It is an arithmetic number, because the mean of its divisors is an integer number (190303840).

Almost surely, 2^1401111433 is an apocalyptic number.

It is an amenable number.

1401111433 is a deficient number, since it is larger than the sum of its proper divisors (121319287).

1401111433 is a wasteful number, since it uses less digits than its factorization.

1401111433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2378847.

The product of its (nonzero) digits is 144, while the sum is 19.

The square root of 1401111433 is about 37431.4230693945. The cubic root of 1401111433 is about 1118.9848989692.

Adding to 1401111433 its reverse (3341111041), we get a palindrome (4742222474).

The spelling of 1401111433 in words is "one billion, four hundred one million, one hundred eleven thousand, four hundred thirty-three".