1401113414411 has 4 divisors (see below), whose sum is σ = 1401915427272. Its totient is φ = 1400311401552.

The previous prime is 1401113414383. The next prime is 1401113414423. The reversal of 1401113414411 is 1144143111041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1401113414411 - 2²² = 1401109220107 is a prime.

It is a super-3 number, since 3×1401113414411³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401113414011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401003810 + ... + 401007303.

It is an arithmetic number, because the mean of its divisors is an integer number (350478856818).

Almost surely, 2^{1401113414411} is an apocalyptic number.

1401113414411 is a deficient number, since it is larger than the sum of its proper divisors (802012861).

1401113414411 is an equidigital number, since it uses as much as digits as its factorization.

1401113414411 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 802012860.

The product of its (nonzero) digits is 768, while the sum is 26.

Adding to 1401113414411 its reverse (1144143111041), we get a palindrome (2545256525452).

The spelling of 1401113414411 in words is "one trillion, four hundred one billion, one hundred thirteen million, four hundred fourteen thousand, four hundred eleven".