140111343131 has 4 divisors (see below), whose sum is σ = 140287142352. Its totient is φ = 139935543912.

The previous prime is 140111343103. The next prime is 140111343173. The reversal of 140111343131 is 131343111041.

140111343131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131343111041 = 8821 ⋅14889821.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140111343131 is a prime.

It is a super-2 number, since 2×140111343131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140111343097 and 140111343106.

It is not an unprimeable number, because it can be changed into a prime (140111343191) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87898415 + ... + 87900008.

It is an arithmetic number, because the mean of its divisors is an integer number (35071785588).

Almost surely, 2^140111343131 is an apocalyptic number.

140111343131 is a deficient number, since it is larger than the sum of its proper divisors (175799221).

140111343131 is an equidigital number, since it uses as much as digits as its factorization.

140111343131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 175799220.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 140111343131 its reverse (131343111041), we get a palindrome (271454454172).

The spelling of 140111343131 in words is "one hundred forty billion, one hundred eleven million, three hundred forty-three thousand, one hundred thirty-one".