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14011230315 = 35934082021
BaseRepresentation
bin11010000110010001…
…00110100001101011
31100011110121020200010
431003020212201223
5212143333332230
610234153143003
71004132330655
oct150310464153
940143536603
1014011230315
115a3aa79795
1228703baa63
131423a41734
1496cb9b6d5
155701009b0
hex34322686b

14011230315 has 8 divisors (see below), whose sum is σ = 22417968528. Its totient is φ = 7472656160.

The previous prime is 14011230307. The next prime is 14011230329. The reversal of 14011230315 is 51303211041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14011230315 - 23 = 14011230307 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14011230291 and 14011230300.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 467040996 + ... + 467041025.

It is an arithmetic number, because the mean of its divisors is an integer number (2802246066).

Almost surely, 214011230315 is an apocalyptic number.

14011230315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

14011230315 is a deficient number, since it is larger than the sum of its proper divisors (8406738213).

14011230315 is an equidigital number, since it uses as much as digits as its factorization.

14011230315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 934082029.

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 14011230315 its reverse (51303211041), we get a palindrome (65314441356).

The spelling of 14011230315 in words is "fourteen billion, eleven million, two hundred thirty thousand, three hundred fifteen".

Divisors: 1 3 5 15 934082021 2802246063 4670410105 14011230315