1401123203131 has 4 divisors (see below), whose sum is σ = 1401446270232. Its totient is φ = 1400800136032.

The previous prime is 1401123203113. The next prime is 1401123203143. The reversal of 1401123203131 is 1313023211041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1401123203131 - 2¹⁷ = 1401123072059 is a prime.

It is a super-2 number, since 2×1401123203131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401123203191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161527045 + ... + 161535718.

It is an arithmetic number, because the mean of its divisors is an integer number (350361567558).

Almost surely, 2^{1401123203131} is an apocalyptic number.

1401123203131 is a deficient number, since it is larger than the sum of its proper divisors (323067101).

1401123203131 is an equidigital number, since it uses as much as digits as its factorization.

1401123203131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 323067100.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1401123203131 its reverse (1313023211041), we get a palindrome (2714146414172).

The spelling of 1401123203131 in words is "one trillion, four hundred one billion, one hundred twenty-three million, two hundred three thousand, one hundred thirty-one".