Search a number
-
+
14011234524345 = 35934082301623
BaseRepresentation
bin1100101111100011111010…
…1010000001110010111001
31211121110110000122220220210
43023320332222001302321
53314030002014234340
645444401113541333
72644164311261622
oct313707652016271
954543400586823
1014011234524345
114512149687053
1216a357a114849
137a833b632ca6
1436620c54aa49
151946e7366180
hexcbe3ea81cb9

14011234524345 has 8 divisors (see below), whose sum is σ = 22417975238976. Its totient is φ = 7472658412976.

The previous prime is 14011234524337. The next prime is 14011234524379. The reversal of 14011234524345 is 54342543211041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14011234524345 - 23 = 14011234524337 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 467041150797 + ... + 467041150826.

It is an arithmetic number, because the mean of its divisors is an integer number (2802246904872).

Almost surely, 214011234524345 is an apocalyptic number.

14011234524345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

14011234524345 is a deficient number, since it is larger than the sum of its proper divisors (8406740714631).

14011234524345 is an equidigital number, since it uses as much as digits as its factorization.

14011234524345 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 934082301631.

The product of its (nonzero) digits is 230400, while the sum is 39.

Adding to 14011234524345 its reverse (54342543211041), we get a palindrome (68353777735386).

The spelling of 14011234524345 in words is "fourteen trillion, eleven billion, two hundred thirty-four million, five hundred twenty-four thousand, three hundred forty-five".

Divisors: 1 3 5 15 934082301623 2802246904869 4670411508115 14011234524345