Base | Representation |
---|---|
bin | 1100101111100011111100… |
… | …0110111100010011000011 |
3 | 1211121110110112221000020212 |
4 | 3023320333012330103003 |
5 | 3314030010434312003 |
6 | 45444401544224335 |
7 | 2644164432561014 |
oct | 313707706742303 |
9 | 54543415830225 |
10 | 14011242104003 |
11 | 4512152993831 |
12 | 16a358076b0ab |
13 | 7a8340087cb1 |
14 | 36620d56100b |
15 | 1946e7d61dd8 |
hex | cbe3f1bc4c3 |
14011242104003 has 4 divisors (see below), whose sum is σ = 14040493131840. Its totient is φ = 13981991076168.
The previous prime is 14011242103981. The next prime is 14011242104053. The reversal of 14011242104003 is 30040124211041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14011242104003 - 242 = 9613195592899 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 14011242104003.
It is not an unprimeable number, because it can be changed into a prime (14011242104053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14625513200 + ... + 14625514157.
It is an arithmetic number, because the mean of its divisors is an integer number (3510123282960).
Almost surely, 214011242104003 is an apocalyptic number.
14011242104003 is a deficient number, since it is larger than the sum of its proper divisors (29251027837).
14011242104003 is an equidigital number, since it uses as much as digits as its factorization.
14011242104003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29251027836.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 14011242104003 its reverse (30040124211041), we get a palindrome (44051366315044).
The spelling of 14011242104003 in words is "fourteen trillion, eleven billion, two hundred forty-two million, one hundred four thousand, three".
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