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140112433 = 598926683
BaseRepresentation
bin10000101100111…
…11001000110001
3100202122110010101
420112133020301
5241332044213
621523032401
73320636026
oct1026371061
9322573111
10140112433
11720a95aa
123ab0b701
1323049586
141487354d
15c479bdd
hex859f231

140112433 has 8 divisors (see below), whose sum is σ = 144093600. Its totient is φ = 136184928.

The previous prime is 140112431. The next prime is 140112437. The reversal of 140112433 is 334211041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 140112433 - 21 = 140112431 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 140112433.

It is not an unprimeable number, because it can be changed into a prime (140112431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8091 + ... + 18592.

It is an arithmetic number, because the mean of its divisors is an integer number (18011700).

Almost surely, 2140112433 is an apocalyptic number.

It is an amenable number.

140112433 is a deficient number, since it is larger than the sum of its proper divisors (3981167).

140112433 is an equidigital number, since it uses as much as digits as its factorization.

140112433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26831.

The product of its (nonzero) digits is 288, while the sum is 19.

The square root of 140112433 is about 11836.9097740922. The cubic root of 140112433 is about 519.3883748220.

Adding to 140112433 its reverse (334211041), we get a palindrome (474323474).

The spelling of 140112433 in words is "one hundred forty million, one hundred twelve thousand, four hundred thirty-three".

Divisors: 1 59 89 5251 26683 1574297 2374787 140112433