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14011303113 = 321556811457
BaseRepresentation
bin11010000110010001…
…11000010011001001
31100011110201221112100
431003020320103021
5212143343144423
610234154504013
71004133053133
oct150310702311
940143657470
1014011303113
115a40019455
122870435009
131423a68902
1496cbba053
15570117343
hex3432384c9

14011303113 has 6 divisors (see below), whose sum is σ = 20238548954. Its totient is φ = 9340868736.

The previous prime is 14011303081. The next prime is 14011303121. The reversal of 14011303113 is 31130311041.

It can be written as a sum of positive squares in only one way, i.e., 13860823824 + 150479289 = 117732^2 + 12267^2 .

It is not a de Polignac number, because 14011303113 - 25 = 14011303081 is a prime.

It is a super-2 number, since 2×140113031132 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14011303193) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 778405720 + ... + 778405737.

Almost surely, 214011303113 is an apocalyptic number.

It is an amenable number.

14011303113 is a deficient number, since it is larger than the sum of its proper divisors (6227245841).

14011303113 is a wasteful number, since it uses less digits than its factorization.

14011303113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1556811463 (or 1556811460 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 14011303113 its reverse (31130311041), we get a palindrome (45141614154).

The spelling of 14011303113 in words is "fourteen billion, eleven million, three hundred three thousand, one hundred thirteen".

Divisors: 1 3 9 1556811457 4670434371 14011303113