14011303243241 has 4 divisors (see below), whose sum is σ = 14015240112000. Its totient is φ = 14007366374484.

The previous prime is 14011303243177. The next prime is 14011303243279. The reversal of 14011303243241 is 14234230311041.

14011303243241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14011303243241 - 2⁶ = 14011303243177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14011303240241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1968429041 + ... + 1968436158.

It is an arithmetic number, because the mean of its divisors is an integer number (3503810028000).

Almost surely, 2^{14011303243241} is an apocalyptic number.

It is an amenable number.

14011303243241 is a deficient number, since it is larger than the sum of its proper divisors (3936868759).

14011303243241 is an equidigital number, since it uses as much as digits as its factorization.

14011303243241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3936868758.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14011303243241 its reverse (14234230311041), we get a palindrome (28245533554282).

The spelling of 14011303243241 in words is "fourteen trillion, eleven billion, three hundred three million, two hundred forty-three thousand, two hundred forty-one".