Base | Representation |
---|---|
bin | 1100101111100100001101… |
… | …1010110100101001011011 |
3 | 1211121110122121000021012111 |
4 | 3023321003122310221123 |
5 | 3314030132443040121 |
6 | 45444413050253151 |
7 | 2644166301360463 |
oct | 313710332645133 |
9 | 54543577007174 |
10 | 14011314424411 |
11 | 451218a79a167 |
12 | 16a35a0a271b7 |
13 | 7a8352059a35 |
14 | 366218dc8ba3 |
15 | 1946ee39a2e1 |
hex | cbe436b4a5b |
14011314424411 has 8 divisors (see below), whose sum is σ = 14062039183280. Its totient is φ = 13960590690528.
The previous prime is 14011314424369. The next prime is 14011314424417. The reversal of 14011314424411 is 11442441311041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14011314424411 - 215 = 14011314391643 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14011314424417) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36817060 + ... + 37195678.
It is an arithmetic number, because the mean of its divisors is an integer number (1757754897910).
Almost surely, 214011314424411 is an apocalyptic number.
14011314424411 is a deficient number, since it is larger than the sum of its proper divisors (50724758869).
14011314424411 is a wasteful number, since it uses less digits than its factorization.
14011314424411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 512493.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 14011314424411 its reverse (11442441311041), we get a palindrome (25453755735452).
The spelling of 14011314424411 in words is "fourteen trillion, eleven billion, three hundred fourteen million, four hundred twenty-four thousand, four hundred eleven".
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