Base | Representation |
---|---|
bin | 11010000110010010… |
… | …00001100100111011 |
3 | 1100011110210212122211 |
4 | 31003021001210323 |
5 | 212143400403430 |
6 | 10234155355551 |
7 | 1004133302002 |
oct | 150311014473 |
9 | 40143725584 |
10 | 14011341115 |
11 | 5a40044a62 |
12 | 2870452bb7 |
13 | 1423a7ccb5 |
14 | 96cbc9c39 |
15 | 57012372a |
hex | 34324193b |
14011341115 has 8 divisors (see below), whose sum is σ = 17268031440. Its totient is φ = 10906124832.
The previous prime is 14011341083. The next prime is 14011341119. The reversal of 14011341115 is 51114311041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14011341115 - 25 = 14011341083 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14011341119) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37868305 + ... + 37868674.
It is an arithmetic number, because the mean of its divisors is an integer number (2158503930).
Almost surely, 214011341115 is an apocalyptic number.
14011341115 is a deficient number, since it is larger than the sum of its proper divisors (3256690325).
14011341115 is an equidigital number, since it uses as much as digits as its factorization.
14011341115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 75737021.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 14011341115 its reverse (51114311041), we get a palindrome (65125652156).
The spelling of 14011341115 in words is "fourteen billion, eleven million, three hundred forty-one thousand, one hundred fifteen".
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