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14011341115 = 53775736979
BaseRepresentation
bin11010000110010010…
…00001100100111011
31100011110210212122211
431003021001210323
5212143400403430
610234155355551
71004133302002
oct150311014473
940143725584
1014011341115
115a40044a62
122870452bb7
131423a7ccb5
1496cbc9c39
1557012372a
hex34324193b

14011341115 has 8 divisors (see below), whose sum is σ = 17268031440. Its totient is φ = 10906124832.

The previous prime is 14011341083. The next prime is 14011341119. The reversal of 14011341115 is 51114311041.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14011341115 - 25 = 14011341083 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14011341119) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37868305 + ... + 37868674.

It is an arithmetic number, because the mean of its divisors is an integer number (2158503930).

Almost surely, 214011341115 is an apocalyptic number.

14011341115 is a deficient number, since it is larger than the sum of its proper divisors (3256690325).

14011341115 is an equidigital number, since it uses as much as digits as its factorization.

14011341115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75737021.

The product of its (nonzero) digits is 240, while the sum is 22.

Adding to 14011341115 its reverse (51114311041), we get a palindrome (65125652156).

The spelling of 14011341115 in words is "fourteen billion, eleven million, three hundred forty-one thousand, one hundred fifteen".

Divisors: 1 5 37 185 75736979 378684895 2802268223 14011341115