140113521131 has 4 divisors (see below), whose sum is σ = 147487917000. Its totient is φ = 132739125264.

The previous prime is 140113521103. The next prime is 140113521167. The reversal of 140113521131 is 131125311041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131125311041 = 59 ⋅2222462899.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-140113521131 is a prime.

It is a super-2 number, since 2×140113521131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140113521097 and 140113521106.

It is not an unprimeable number, because it can be changed into a prime (140113521931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3687197906 + ... + 3687197943.

It is an arithmetic number, because the mean of its divisors is an integer number (36871979250).

Almost surely, 2^140113521131 is an apocalyptic number.

140113521131 is a deficient number, since it is larger than the sum of its proper divisors (7374395869).

140113521131 is an equidigital number, since it uses as much as digits as its factorization.

140113521131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7374395868.

The product of its (nonzero) digits is 360, while the sum is 23.

Adding to 140113521131 its reverse (131125311041), we get a palindrome (271238832172).

The spelling of 140113521131 in words is "one hundred forty billion, one hundred thirteen million, five hundred twenty-one thousand, one hundred thirty-one".