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140120000331 = 346706666777
BaseRepresentation
bin1000001001111111001…
…1011000011101001011
3111101200012111112020220
42002133303120131023
54243431210002311
6144211545521123
713060206231333
oct2023763303513
9441605445226
10140120000331
11544740a6173
12231a5aa31a3
13102a06b90cc
146ad35480c3
1539a1527206
hex209fcd874b

140120000331 has 4 divisors (see below), whose sum is σ = 186826667112. Its totient is φ = 93413333552.

The previous prime is 140120000327. The next prime is 140120000333. The reversal of 140120000331 is 133000021041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140120000331 - 22 = 140120000327 is a prime.

It is a super-2 number, since 2×1401200003312 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 140120000331.

It is not an unprimeable number, because it can be changed into a prime (140120000333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23353333386 + ... + 23353333391.

It is an arithmetic number, because the mean of its divisors is an integer number (46706666778).

Almost surely, 2140120000331 is an apocalyptic number.

140120000331 is a deficient number, since it is larger than the sum of its proper divisors (46706666781).

140120000331 is an equidigital number, since it uses as much as digits as its factorization.

140120000331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 46706666780.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 140120000331 its reverse (133000021041), we get a palindrome (273120021372).

The spelling of 140120000331 in words is "one hundred forty billion, one hundred twenty million, three hundred thirty-one", and thus it is an aban number.

Divisors: 1 3 46706666777 140120000331