Base | Representation |
---|---|
bin | 1100101111100110111001… |
… | …0000111001110011110011 |
3 | 1211121112111200121002212011 |
4 | 3023321232100321303303 |
5 | 3314033121002310103 |
6 | 45445012245143351 |
7 | 2644223150264545 |
oct | 313715620716363 |
9 | 54545450532764 |
10 | 14012033244403 |
11 | 4512519523277 |
12 | 16a37616bab57 |
13 | 7a8437c583cc |
14 | 366286661695 |
15 | 194742538d6d |
hex | cbe6e439cf3 |
14012033244403 has 8 divisors (see below), whose sum is σ = 14243591888480. Its totient is φ = 13780534380480.
The previous prime is 14012033244389. The next prime is 14012033244421. The reversal of 14012033244403 is 30444233021041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14012033244403 - 25 = 14012033244371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14012033244463) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14472258 + ... + 15410071.
It is an arithmetic number, because the mean of its divisors is an integer number (1780448986060).
Almost surely, 214012033244403 is an apocalyptic number.
14012033244403 is a deficient number, since it is larger than the sum of its proper divisors (231558644077).
14012033244403 is an equidigital number, since it uses as much as digits as its factorization.
14012033244403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29890077.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 14012033244403 its reverse (30444233021041), we get a palindrome (44456266265444).
The spelling of 14012033244403 in words is "fourteen trillion, twelve billion, thirty-three million, two hundred forty-four thousand, four hundred three".
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