Base | Representation |
---|---|
bin | 1100101111100111001000… |
… | …1111101010111111101011 |
3 | 1211121112200100021012002012 |
4 | 3023321302033222333223 |
5 | 3314033240101433233 |
6 | 45445023032430135 |
7 | 2644224621044204 |
oct | 313716217527753 |
9 | 54545610235065 |
10 | 14012100030443 |
11 | 4512553199649 |
12 | 16a377bb4834b |
13 | 7a8448a40088 |
14 | 3662914885ab |
15 | 19474832c548 |
hex | cbe723eafeb |
14012100030443 has 4 divisors (see below), whose sum is σ = 14072237799048. Its totient is φ = 13951962261840.
The previous prime is 14012100030427. The next prime is 14012100030457. The reversal of 14012100030443 is 34403000121041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14012100030443 - 24 = 14012100030427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14012100030493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30068883953 + ... + 30068884418.
It is an arithmetic number, because the mean of its divisors is an integer number (3518059449762).
Almost surely, 214012100030443 is an apocalyptic number.
14012100030443 is a deficient number, since it is larger than the sum of its proper divisors (60137768605).
14012100030443 is an equidigital number, since it uses as much as digits as its factorization.
14012100030443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60137768604.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 14012100030443 its reverse (34403000121041), we get a palindrome (48415100151484).
The spelling of 14012100030443 in words is "fourteen trillion, twelve billion, one hundred million, thirty thousand, four hundred forty-three".
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