1401302111321 has 4 divisors (see below), whose sum is σ = 1601488127232. Its totient is φ = 1201116095412.

The previous prime is 1401302111291. The next prime is 1401302111329. The reversal of 1401302111321 is 1231112031041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1401302111321 - 2⁶ = 1401302111257 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1401302111293 and 1401302111302.

It is not an unprimeable number, because it can be changed into a prime (1401302111329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100093007945 + ... + 100093007958.

It is an arithmetic number, because the mean of its divisors is an integer number (400372031808).

Almost surely, 2^{1401302111321} is an apocalyptic number.

It is an amenable number.

1401302111321 is a deficient number, since it is larger than the sum of its proper divisors (200186015911).

1401302111321 is an equidigital number, since it uses as much as digits as its factorization.

1401302111321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200186015910.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1401302111321 its reverse (1231112031041), we get a palindrome (2632414142362).

The spelling of 1401302111321 in words is "one trillion, four hundred one billion, three hundred two million, one hundred eleven thousand, three hundred twenty-one".