Base | Representation |
---|---|
bin | 10100011001000100101… |
… | …111001000010101101001 |
3 | 11221222000212202221111111 |
4 | 110121010233020111221 |
5 | 140424342002402410 |
6 | 2551430515030321 |
7 | 203145555044155 |
oct | 24310457102551 |
9 | 4858025687444 |
10 | 1401312544105 |
11 | 4a0325443091 |
12 | 1a770089b3a1 |
13 | a21b28146a6 |
14 | 4bb76a74065 |
15 | 266b84cbb8a |
hex | 14644bc8569 |
1401312544105 has 16 divisors (see below), whose sum is σ = 1827178329600. Its totient is φ = 1027787806080.
The previous prime is 1401312544019. The next prime is 1401312544123. The reversal of 1401312544105 is 5014452131041.
It is not a de Polignac number, because 1401312544105 - 215 = 1401312511337 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 237910900 + ... + 237916789.
It is an arithmetic number, because the mean of its divisors is an integer number (114198645600).
Almost surely, 21401312544105 is an apocalyptic number.
It is an amenable number.
1401312544105 is a deficient number, since it is larger than the sum of its proper divisors (425865785495).
1401312544105 is a wasteful number, since it uses less digits than its factorization.
1401312544105 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 475827744.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 1401312544105 its reverse (5014452131041), we get a palindrome (6415764675146).
The spelling of 1401312544105 in words is "one trillion, four hundred one billion, three hundred twelve million, five hundred forty-four thousand, one hundred five".
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