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14013234041 = 42131332611
BaseRepresentation
bin11010000110100000…
…01111101101111001
31100011121101001021012
431003100033231321
5212144341442131
610234304123305
71004155344512
oct150320175571
940147331235
1014013234041
115a41118164
122871006535
131424293781
1496d15da09
1557039952b
hex34340fb79

14013234041 has 4 divisors (see below), whose sum is σ = 14013608784. Its totient is φ = 14012859300.

The previous prime is 14013233953. The next prime is 14013234047. The reversal of 14013234041 is 14043231041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14013234041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14013233998 and 14013234016.

It is not an unprimeable number, because it can be changed into a prime (14013234047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 124175 + ... + 208436.

It is an arithmetic number, because the mean of its divisors is an integer number (3503402196).

Almost surely, 214013234041 is an apocalyptic number.

It is an amenable number.

14013234041 is a deficient number, since it is larger than the sum of its proper divisors (374743).

14013234041 is an equidigital number, since it uses as much as digits as its factorization.

14013234041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 374742.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14013234041 its reverse (14043231041), we get a palindrome (28056465082).

The spelling of 14013234041 in words is "fourteen billion, thirteen million, two hundred thirty-four thousand, forty-one".

Divisors: 1 42131 332611 14013234041