Base | Representation |
---|---|
bin | 10100011001000101110… |
… | …001110110001010011011 |
3 | 11221222002002200111011201 |
4 | 110121011301312022123 |
5 | 140424410442031212 |
6 | 2551432341535031 |
7 | 203146156515121 |
oct | 24310561661233 |
9 | 4858062614151 |
10 | 1401330033307 |
11 | 4a03342a8a76 |
12 | 1a7706714477 |
13 | a21b6329029 |
14 | 4bb79107911 |
15 | 266b9cd3b57 |
hex | 14645c7629b |
1401330033307 has 4 divisors (see below), whose sum is σ = 1401384834720. Its totient is φ = 1401275231896.
The previous prime is 1401330033289. The next prime is 1401330033329. The reversal of 1401330033307 is 7033300331041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1401330033307 - 27 = 1401330033179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1401330033007) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27362332 + ... + 27413497.
It is an arithmetic number, because the mean of its divisors is an integer number (350346208680).
Almost surely, 21401330033307 is an apocalyptic number.
1401330033307 is a deficient number, since it is larger than the sum of its proper divisors (54801413).
1401330033307 is an equidigital number, since it uses as much as digits as its factorization.
1401330033307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54801412.
The product of its (nonzero) digits is 6804, while the sum is 28.
Adding to 1401330033307 its reverse (7033300331041), we get a palindrome (8434630364348).
The spelling of 1401330033307 in words is "one trillion, four hundred one billion, three hundred thirty million, thirty-three thousand, three hundred seven".
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