14013412121 has 4 divisors (see below), whose sum is σ = 14016744144. Its totient is φ = 14010080100.

The previous prime is 14013412117. The next prime is 14013412139. The reversal of 14013412121 is 12121431041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 12121431041 = 2857 ⋅4242713.

It is a cyclic number.

It is not a de Polignac number, because 14013412121 - 2² = 14013412117 is a prime.

It is a super-3 number, since 3×14013412121³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14013412093 and 14013412102.

It is not an unprimeable number, because it can be changed into a prime (14013412151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1659695 + ... + 1668116.

It is an arithmetic number, because the mean of its divisors is an integer number (3504186036).

Almost surely, 2^14013412121 is an apocalyptic number.

It is an amenable number.

14013412121 is a deficient number, since it is larger than the sum of its proper divisors (3332023).

14013412121 is an equidigital number, since it uses as much as digits as its factorization.

14013412121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3332022.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 14013412121 its reverse (12121431041), we get a palindrome (26134843162).

The spelling of 14013412121 in words is "fourteen billion, thirteen million, four hundred twelve thousand, one hundred twenty-one".