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1401342344011 = 5756512434361
BaseRepresentation
bin10100011001000110100…
…000110011101101001011
311221222002221211221021201
4110121012200303231023
5140424422120002021
62551433501445031
7203146366250311
oct24310640635513
94858087757251
101401342344011
114a0340247205
121a770a870777
13a21b8a4957c
144bb7a9d00b1
15266bae16591
hex14646833b4b

1401342344011 has 4 divisors (see below), whose sum is σ = 1401345354024. Its totient is φ = 1401339334000.

The previous prime is 1401342343949. The next prime is 1401342344021. The reversal of 1401342344011 is 1104432431041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1401342344011 - 231 = 1399194860363 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1401342344021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641530 + ... + 1792831.

It is an arithmetic number, because the mean of its divisors is an integer number (350336338506).

Almost surely, 21401342344011 is an apocalyptic number.

1401342344011 is a deficient number, since it is larger than the sum of its proper divisors (3010013).

1401342344011 is an equidigital number, since it uses as much as digits as its factorization.

1401342344011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3010012.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1401342344011 its reverse (1104432431041), we get a palindrome (2505774775052).

The spelling of 1401342344011 in words is "one trillion, four hundred one billion, three hundred forty-two million, three hundred forty-four thousand, eleven".

Divisors: 1 575651 2434361 1401342344011