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14013455035 = 51927763687
BaseRepresentation
bin11010000110100010…
…00101101010111011
31100011121210021102011
431003101011222323
5212144421030120
610234312550351
71004160255016
oct150321055273
940147707364
1014013455035
115a412591a8
1228710b23b7
131424340238
1496d1ba37d
155703dec5a
hex343445abb

14013455035 has 12 divisors (see below), whose sum is σ = 17747790768. Its totient is φ = 10620722448.

The previous prime is 14013454993. The next prime is 14013455059. The reversal of 14013455035 is 53055431041.

14013455035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 14013455035 - 29 = 14013454523 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14013454988 and 14013455006.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3880039 + ... + 3883648.

It is an arithmetic number, because the mean of its divisors is an integer number (1478982564).

Almost surely, 214013455035 is an apocalyptic number.

14013455035 is a deficient number, since it is larger than the sum of its proper divisors (3734335733).

14013455035 is an equidigital number, since it uses as much as digits as its factorization.

14013455035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7763730 (or 7763711 counting only the distinct ones).

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 14013455035 its reverse (53055431041), we get a palindrome (67068886076).

The spelling of 14013455035 in words is "fourteen billion, thirteen million, four hundred fifty-five thousand, thirty-five".

Divisors: 1 5 19 95 361 1805 7763687 38818435 147510053 737550265 2802691007 14013455035