Base | Representation |
---|---|
bin | 1100101111101100001110… |
… | …0011000001011011001011 |
3 | 1211121200012101220221111120 |
4 | 3023323003203001123023 |
5 | 3314044033244320142 |
6 | 45445410240330323 |
7 | 2644303463063463 |
oct | 313730343013313 |
9 | 54550171827446 |
10 | 14013464057547 |
11 | 4513093148379 |
12 | 16a3aa09139a3 |
13 | 7a8605504cc6 |
14 | 3663806b4ba3 |
15 | 1947c7e687ec |
hex | cbec38c16cb |
14013464057547 has 4 divisors (see below), whose sum is σ = 18684618743400. Its totient is φ = 9342309371696.
The previous prime is 14013464057539. The next prime is 14013464057561. The reversal of 14013464057547 is 74575046431041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14013464057547 - 23 = 14013464057539 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14013464057547.
It is not an unprimeable number, because it can be changed into a prime (14013464057347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2335577342922 + ... + 2335577342927.
It is an arithmetic number, because the mean of its divisors is an integer number (4671154685850).
Almost surely, 214013464057547 is an apocalyptic number.
14013464057547 is a deficient number, since it is larger than the sum of its proper divisors (4671154685853).
14013464057547 is an equidigital number, since it uses as much as digits as its factorization.
14013464057547 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4671154685852.
The product of its (nonzero) digits is 5644800, while the sum is 51.
The spelling of 14013464057547 in words is "fourteen trillion, thirteen billion, four hundred sixty-four million, fifty-seven thousand, five hundred forty-seven".
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