1401430244131 has 4 divisors (see below), whose sum is σ = 1402779071200. Its totient is φ = 1400081417064.

The previous prime is 1401430244083. The next prime is 1401430244189. The reversal of 1401430244131 is 1314420341041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1401430244131 - 2¹¹ = 1401430242083 is a prime.

It is a super-2 number, since 2×1401430244131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1401430244131.

It is not an unprimeable number, because it can be changed into a prime (1401430244831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 674411976 + ... + 674414053.

It is an arithmetic number, because the mean of its divisors is an integer number (350694767800).

Almost surely, 2^{1401430244131} is an apocalyptic number.

1401430244131 is a deficient number, since it is larger than the sum of its proper divisors (1348827069).

1401430244131 is a wasteful number, since it uses less digits than its factorization.

1401430244131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1348827068.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 1401430244131 its reverse (1314420341041), we get a palindrome (2715850585172).

The spelling of 1401430244131 in words is "one trillion, four hundred one billion, four hundred thirty million, two hundred forty-four thousand, one hundred thirty-one".