Base | Representation |
---|---|
bin | 1100101111101111011111… |
… | …0000110111010100111001 |
3 | 1211121202110110100120210102 |
4 | 3023323313300313110321 |
5 | 3314102332031221213 |
6 | 45450033213125145 |
7 | 2644334261245340 |
oct | 313736760672471 |
9 | 54552413316712 |
10 | 14014340101433 |
11 | 45134a26a8091 |
12 | 16a40a61897b5 |
13 | 7a8714b61679 |
14 | 366424b96b57 |
15 | 194829d12158 |
hex | cbef7c37539 |
14014340101433 has 8 divisors (see below), whose sum is σ = 16533046387200. Its totient is φ = 11624798240640.
The previous prime is 14014340101387. The next prime is 14014340101451. The reversal of 14014340101433 is 33410104341041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14014340101433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14014340101396 and 14014340101405.
It is not an unprimeable number, because it can be changed into a prime (14014340109433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32291106008 + ... + 32291106441.
It is an arithmetic number, because the mean of its divisors is an integer number (2066630798400).
Almost surely, 214014340101433 is an apocalyptic number.
It is an amenable number.
14014340101433 is a deficient number, since it is larger than the sum of its proper divisors (2518706285767).
14014340101433 is an equidigital number, since it uses as much as digits as its factorization.
14014340101433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64582212487.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 14014340101433 its reverse (33410104341041), we get a palindrome (47424444442474).
The spelling of 14014340101433 in words is "fourteen trillion, fourteen billion, three hundred forty million, one hundred one thousand, four hundred thirty-three".
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