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14015412553 = 28149876913
BaseRepresentation
bin11010000110110001…
…00011100101001001
31100011202110201121211
431003120203211021
5212200421200203
610234422533121
71004213020042
oct150330434511
940152421554
1014015412553
115a4237598a
1228718971a1
13142487722c
1496d5698c9
15570679c6d
hex343623949

14015412553 has 4 divisors (see below), whose sum is σ = 14065289748. Its totient is φ = 13965535360.

The previous prime is 14015412539. The next prime is 14015412563. The reversal of 14015412553 is 35521451041.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9175149369 + 4840263184 = 95787^2 + 69572^2 .

It is a cyclic number.

It is not a de Polignac number, because 14015412553 - 221 = 14013315401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14015412563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24938176 + ... + 24938737.

It is an arithmetic number, because the mean of its divisors is an integer number (3516322437).

Almost surely, 214015412553 is an apocalyptic number.

It is an amenable number.

14015412553 is a deficient number, since it is larger than the sum of its proper divisors (49877195).

14015412553 is an equidigital number, since it uses as much as digits as its factorization.

14015412553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 49877194.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 14015412553 its reverse (35521451041), we get a palindrome (49536863594).

The spelling of 14015412553 in words is "fourteen billion, fifteen million, four hundred twelve thousand, five hundred fifty-three".

Divisors: 1 281 49876913 14015412553