Base | Representation |
---|---|
bin | 11010000110110001… |
… | …11010010000101011 |
3 | 1100011202122110001111 |
4 | 31003120322100223 |
5 | 212200432133301 |
6 | 10234424531151 |
7 | 1004213554633 |
oct | 150330722053 |
9 | 40152573044 |
10 | 14015505451 |
11 | 5a42429762 |
12 | 2871920ab7 |
13 | 14248aa5bc |
14 | 96d5916c3 |
15 | 570697551 |
hex | 34363a42b |
14015505451 has 4 divisors (see below), whose sum is σ = 14017498552. Its totient is φ = 14013512352.
The previous prime is 14015505443. The next prime is 14015505461. The reversal of 14015505451 is 15450551041.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15450551041 = 56897 ⋅271553.
It is a cyclic number.
It is not a de Polignac number, because 14015505451 - 23 = 14015505443 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14015505431) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 985965 + ... + 1000078.
It is an arithmetic number, because the mean of its divisors is an integer number (3504374638).
Almost surely, 214015505451 is an apocalyptic number.
14015505451 is a deficient number, since it is larger than the sum of its proper divisors (1993101).
14015505451 is an equidigital number, since it uses as much as digits as its factorization.
14015505451 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1993100.
The product of its (nonzero) digits is 10000, while the sum is 31.
The spelling of 14015505451 in words is "fourteen billion, fifteen million, five hundred five thousand, four hundred fifty-one".
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