14020230133433 has 4 divisors (see below), whose sum is σ = 14250069971748. Its totient is φ = 13790390295120.

The previous prime is 14020230133411. The next prime is 14020230133501. The reversal of 14020230133433 is 33433103202041.

14020230133433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1563932828329 + 12456297305104 = 1250573^2 + 3529348^2 .

It is a cyclic number.

It is not a de Polignac number, because 14020230133433 - 2¹² = 14020230129337 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14020230133396 and 14020230133405.

It is not an unprimeable number, because it can be changed into a prime (14020290133433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 114919919066 + ... + 114919919187.

It is an arithmetic number, because the mean of its divisors is an integer number (3562517492937).

Almost surely, 2^{14020230133433} is an apocalyptic number.

It is an amenable number.

14020230133433 is a deficient number, since it is larger than the sum of its proper divisors (229839838315).

14020230133433 is an equidigital number, since it uses as much as digits as its factorization.

14020230133433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 229839838314.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 14020230133433 its reverse (33433103202041), we get a palindrome (47453333335474).

The spelling of 14020230133433 in words is "fourteen trillion, twenty billion, two hundred thirty million, one hundred thirty-three thousand, four hundred thirty-three".