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14021110433 = 111274646403
BaseRepresentation
bin11010000111011100…
…10010101010100001
31100012011012012122102
431003232102222201
5212203401013213
610235145020145
71004312320661
oct150356225241
940164165572
1014021110433
115a45607880
122873784655
131425ac0865
149702101a1
15570e03158
hex343b92aa1

14021110433 has 4 divisors (see below), whose sum is σ = 15295756848. Its totient is φ = 12746464020.

The previous prime is 14021110393. The next prime is 14021110457. The reversal of 14021110433 is 33401112041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33401112041 = 113036464731.

It is a cyclic number.

It is not a de Polignac number, because 14021110433 - 216 = 14021044897 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14021110133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 637323191 + ... + 637323212.

It is an arithmetic number, because the mean of its divisors is an integer number (3823939212).

Almost surely, 214021110433 is an apocalyptic number.

It is an amenable number.

14021110433 is a deficient number, since it is larger than the sum of its proper divisors (1274646415).

14021110433 is a wasteful number, since it uses less digits than its factorization.

14021110433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1274646414.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 14021110433 its reverse (33401112041), we get a palindrome (47422222474).

The spelling of 14021110433 in words is "fourteen billion, twenty-one million, one hundred ten thousand, four hundred thirty-three".

Divisors: 1 11 1274646403 14021110433