140213111212433 has 4 divisors (see below), whose sum is σ = 160243555671360. Its totient is φ = 120182666753508.

The previous prime is 140213111212411. The next prime is 140213111212453. The reversal of 140213111212433 is 334212111312041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 140213111212433 - 2²² = 140213107018129 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140213111212396 and 140213111212405.

It is not an unprimeable number, because it can be changed into a prime (140213111212453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10015222229453 + ... + 10015222229466.

It is an arithmetic number, because the mean of its divisors is an integer number (40060888917840).

Almost surely, 2^{140213111212433} is an apocalyptic number.

It is an amenable number.

140213111212433 is a deficient number, since it is larger than the sum of its proper divisors (20030444458927).

140213111212433 is an equidigital number, since it uses as much as digits as its factorization.

140213111212433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20030444458926.

The product of its (nonzero) digits is 3456, while the sum is 29.

Adding to 140213111212433 its reverse (334212111312041), we get a palindrome (474425222524474).

The spelling of 140213111212433 in words is "one hundred forty trillion, two hundred thirteen billion, one hundred eleven million, two hundred twelve thousand, four hundred thirty-three".