Base | Representation |
---|---|
bin | 11111111000010111110101… |
… | …110000010000000010010001 |
3 | 200101110021010002002222002210 |
4 | 133320113311300100002101 |
5 | 121334223400043210213 |
6 | 1214113040442502333 |
7 | 41351036016116421 |
oct | 3770276560200221 |
9 | 611407102088083 |
10 | 140213330444433 |
11 | 40749159755674 |
12 | 138863488049a9 |
13 | 60310a26cb6cc |
14 | 268a50b994481 |
15 | 113240cdd70c3 |
hex | 7f85f5c10091 |
140213330444433 has 16 divisors (see below), whose sum is σ = 191830608144000. Its totient is φ = 91043415515520.
The previous prime is 140213330444413. The next prime is 140213330444461. The reversal of 140213330444433 is 334444033312041.
It is not a de Polignac number, because 140213330444433 - 25 = 140213330444401 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 140213330444391 and 140213330444400.
It is not an unprimeable number, because it can be changed into a prime (140213330444413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 951467038 + ... + 951614391.
It is an arithmetic number, because the mean of its divisors is an integer number (11989413009000).
Almost surely, 2140213330444433 is an apocalyptic number.
It is an amenable number.
140213330444433 is a deficient number, since it is larger than the sum of its proper divisors (51617277699567).
140213330444433 is a wasteful number, since it uses less digits than its factorization.
140213330444433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1903082072.
The product of its (nonzero) digits is 497664, while the sum is 39.
Adding to 140213330444433 its reverse (334444033312041), we get a palindrome (474657363756474).
The spelling of 140213330444433 in words is "one hundred forty trillion, two hundred thirteen billion, three hundred thirty million, four hundred forty-four thousand, four hundred thirty-three".
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