1402133311441 has 4 divisors (see below), whose sum is σ = 1419026483952. Its totient is φ = 1385240138932.

The previous prime is 1402133311433. The next prime is 1402133311459. The reversal of 1402133311441 is 1441133312041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1402133311441 - 2³ = 1402133311433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1402133311471) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8446586131 + ... + 8446586296.

It is an arithmetic number, because the mean of its divisors is an integer number (354756620988).

Almost surely, 2^{1402133311441} is an apocalyptic number.

It is an amenable number.

1402133311441 is a deficient number, since it is larger than the sum of its proper divisors (16893172511).

1402133311441 is an equidigital number, since it uses as much as digits as its factorization.

1402133311441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16893172510.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 1402133311441 its reverse (1441133312041), we get a palindrome (2843266623482).

The spelling of 1402133311441 in words is "one trillion, four hundred two billion, one hundred thirty-three million, three hundred eleven thousand, four hundred forty-one".