Base | Representation |
---|---|
bin | 11111111000011001110010… |
… | …010111110111010001100011 |
3 | 200101110110111210020112102211 |
4 | 133320121302113313101203 |
5 | 121334242140312003210 |
6 | 1214114024131022551 |
7 | 41351141564225155 |
oct | 3770316227672143 |
9 | 611413453215384 |
10 | 140215421203555 |
11 | 4074a031951975 |
12 | 13886830a3aa57 |
13 | 6031346902399 |
14 | 268a669516ad5 |
15 | 11324d172638a |
hex | 7f86725f7463 |
140215421203555 has 8 divisors (see below), whose sum is σ = 168476174925552. Its totient is φ = 112027223975328.
The previous prime is 140215421203523. The next prime is 140215421203577. The reversal of 140215421203555 is 555302124512041.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 140215421203555 - 25 = 140215421203523 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18139119189 + ... + 18139126918.
It is an arithmetic number, because the mean of its divisors is an integer number (21059521865694).
Almost surely, 2140215421203555 is an apocalyptic number.
140215421203555 is a deficient number, since it is larger than the sum of its proper divisors (28260753721997).
140215421203555 is an equidigital number, since it uses as much as digits as its factorization.
140215421203555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36278246885.
The product of its (nonzero) digits is 240000, while the sum is 40.
Adding to 140215421203555 its reverse (555302124512041), we get a palindrome (695517545715596).
The spelling of 140215421203555 in words is "one hundred forty trillion, two hundred fifteen billion, four hundred twenty-one million, two hundred three thousand, five hundred fifty-five".
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