Base | Representation |
---|---|
bin | 11010000111100011… |
… | …01100001100011001 |
3 | 1100012012212110212102 |
4 | 31003301230030121 |
5 | 212204113021213 |
6 | 10235220053145 |
7 | 1004323021436 |
oct | 150361541431 |
9 | 40165773772 |
10 | 14022001433 |
11 | 5a46066240 |
12 | 2873b341b5 |
13 | 142604328b |
14 | 9703a2b8d |
15 | 57102c158 |
hex | 343c6c319 |
14022001433 has 16 divisors (see below), whose sum is σ = 15348864960. Its totient is φ = 12703905600.
The previous prime is 14022001393. The next prime is 14022001447. The reversal of 14022001433 is 33410022041.
It is a cyclic number.
It is not a de Polignac number, because 14022001433 - 218 = 14021739289 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14022001493) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6312263 + ... + 6314483.
It is an arithmetic number, because the mean of its divisors is an integer number (959304060).
Almost surely, 214022001433 is an apocalyptic number.
It is an amenable number.
14022001433 is a deficient number, since it is larger than the sum of its proper divisors (1326863527).
14022001433 is a wasteful number, since it uses less digits than its factorization.
14022001433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3928.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 14022001433 its reverse (33410022041), we get a palindrome (47432023474).
The spelling of 14022001433 in words is "fourteen billion, twenty-two million, one thousand, four hundred thirty-three".
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