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140220135553 = 592376612467
BaseRepresentation
bin1000001010010111000…
…1010111100010000001
3111101221011220220221211
42002211301113202001
54244132323314203
6144225524050121
713062533325631
oct2024561274201
9441834826854
10140220135553
115451567a253
1223213533941
13102b8379314
146b029726c1
1539aa206c6d
hex20a5c57881

140220135553 has 4 divisors (see below), whose sum is σ = 142596748080. Its totient is φ = 137843523028.

The previous prime is 140220135499. The next prime is 140220135563. The reversal of 140220135553 is 355531022041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 355531022041 = 1327348540157.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-140220135553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140220135563) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1188306175 + ... + 1188306292.

It is an arithmetic number, because the mean of its divisors is an integer number (35649187020).

Almost surely, 2140220135553 is an apocalyptic number.

It is an amenable number.

140220135553 is a deficient number, since it is larger than the sum of its proper divisors (2376612527).

140220135553 is an equidigital number, since it uses as much as digits as its factorization.

140220135553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2376612526.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 140220135553 its reverse (355531022041), we get a palindrome (495751157594).

The spelling of 140220135553 in words is "one hundred forty billion, two hundred twenty million, one hundred thirty-five thousand, five hundred fifty-three".

Divisors: 1 59 2376612467 140220135553