140220213020433 has 240 divisors, whose sum is σ = 263570649323520. Its totient is φ = 73634575392000.

The previous prime is 140220213020411. The next prime is 140220213020467. The reversal of 140220213020433 is 334020312022041.

140220213020433 is a `hidden beast` number, since 1 + 4 + 0 + 2 + 202 + 1 + 3 + 0 + 20 + 433 = 666.

It is not a de Polignac number, because 140220213020433 - 2⁹ = 140220213019921 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is a junction number, because it is equal to n+sod(n) for n = 140220213020397 and 140220213020406.

It is not an unprimeable number, because it can be changed into a prime (140220213020233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 24595719483 + ... + 24595725183.

It is an arithmetic number, because the mean of its divisors is an integer number (1098211038848).

Almost surely, 2^{140220213020433} is an apocalyptic number.

140220213020433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

140220213020433 is a deficient number, since it is larger than the sum of its proper divisors (123350436303087).

140220213020433 is a wasteful number, since it uses less digits than its factorization.

140220213020433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7770 (or 7754 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 140220213020433 its reverse (334020312022041), we get a palindrome (474240525042474).

The spelling of 140220213020433 in words is "one hundred forty trillion, two hundred twenty billion, two hundred thirteen million, twenty thousand, four hundred thirty-three".