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140220312131 = 216164886771
BaseRepresentation
bin1000001010010111001…
…0000010101001000011
3111101221012020220011202
42002211302002221003
54244132344442011
6144225531531415
713062534662504
oct2024562025103
9441835226152
10140220312131
115451578a989
12232135b9b6b
13102b840b7c3
146b029babab
1539aa23e23b
hex20a5c82a43

140220312131 has 4 divisors (see below), whose sum is σ = 140285201064. Its totient is φ = 140155423200.

The previous prime is 140220312103. The next prime is 140220312139. The reversal of 140220312131 is 131213022041.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 140220312131 - 210 = 140220311107 is a prime.

It is a super-2 number, since 2×1402203121312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (140220312139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32441225 + ... + 32445546.

It is an arithmetic number, because the mean of its divisors is an integer number (35071300266).

Almost surely, 2140220312131 is an apocalyptic number.

140220312131 is a deficient number, since it is larger than the sum of its proper divisors (64888933).

140220312131 is an equidigital number, since it uses as much as digits as its factorization.

140220312131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64888932.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 140220312131 its reverse (131213022041), we get a palindrome (271433334172).

The spelling of 140220312131 in words is "one hundred forty billion, two hundred twenty million, three hundred twelve thousand, one hundred thirty-one".

Divisors: 1 2161 64886771 140220312131