140221313 has 4 divisors (see below), whose sum is σ = 140955648. Its totient is φ = 139486980.

The previous prime is 140221309. The next prime is 140221397. The reversal of 140221313 is 313122041.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313122041 = 31 ⋅10100711.

It is a cyclic number.

It is not a de Polignac number, because 140221313 - 2² = 140221309 is a prime.

It is a super-3 number, since 3×140221313³ (a number of 25 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 140221291 and 140221300.

It is not an unprimeable number, because it can be changed into a prime (140220313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 366881 + ... + 367262.

It is an arithmetic number, because the mean of its divisors is an integer number (35238912).

Almost surely, 2^140221313 is an apocalyptic number.

It is an amenable number.

140221313 is a deficient number, since it is larger than the sum of its proper divisors (734335).

140221313 is an equidigital number, since it uses as much as digits as its factorization.

140221313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 734334.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 140221313 is about 11841.5080542978. The cubic root of 140221313 is about 519.5228771950.

Adding to 140221313 its reverse (313122041), we get a palindrome (453343354).

The spelling of 140221313 in words is "one hundred forty million, two hundred twenty-one thousand, three hundred thirteen".